Roethlisberger Named AFC Offensive Player of the Week

PITTSBURGH– Steelers quarterback Ben Roethlisberger was named AFC Offensive Player of the Week for his Week 2 performance, it was announced today.

Roethlisberger completed 21-of-27 passes for 369 yards with three touchdowns for a passer rating of 155.8 against the San Francisco 49ers. It marked his 39th career 300-yard game during the regular season and the 31st time he threw at least three touchdowns in a single game during the regular season. Roethlisberger has thrown at least one touchdown pass in 33 straight home games, which is the second-longest active streak and the sixth-longest streak in NFL history.

This marks the 12th time Roethlisberger has been named AFC Offensive Player of the Week and the first time since taking home such honors in back-to-back weeks (Weeks 8-9) in 2014.

This article has been reproduced in a new format and may be missing content or contain faulty links. Please use the Contact Us link in our site footer to report an issue.

Related Content