Woodley AFC Defensive Player of the Week


Woodley Named AFC Defensive Player of the Week Linebacker LaMarr Woodley was named the AFC Defensive Player of the Week for his performance in a 23-20 win over the Baltimore Ravens at Heinz Field on Sunday.

Woodley finished the game with two sacks, a forced fumble, 10 tackles and one pass defensed.

Woodley sacked Ravens quarterback Joe Flacco twice on their final drive of the game, the second one culminating in a forced fumble that Ziggy Hood recovered to seal the victory.

The third-year linebacker leads the Steelers with 11.5 sacks this season and set a Steelers record by recording at least a half-sack in seven consecutive games. The old record of six was set by Greg Lloyd in 1994.

This is his first Defensive Player of the Week honor.

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