Tuitt takes home AFC honor

Stephon Tuitt's impact can be felt each and every week by the defense, and his performance on Sunday against the Baltimore Ravens, in a 28-24 win, was no exception.

That is exactly why the seventh-year defense end was named the AFC Defensive Player of the Week for Week 8 of the NFL season, the first time he has won the honor.

Tuitt finished the game with two sacks for a combined loss of 15 yards, nine tackles, including eight solo stops, three tackles for a loss, and three quarterback hurries.

After the game Tuitt acknowledged the defense can play better, but they did step up late shutting the Ravens down on their final two drives.

"This wasn't our best defensive performance game, at all, but those two drives that we did those stops on were the most important," said Tuitt. "We were in an adversity situation and we overcame it. They're a good team. We need to do better defensively in these moments, and we will.

"They're a good team. They're a great team, not just a good team –they're a great team. To come here, away, and to steal a win, especially against a tough opponent and a division opponent like the Ravens, is big."

Take a look at the best photos of the Steelers defense from the Week 8 game against the Baltimore Ravens at M&T Bank Stadium

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